Optimal. Leaf size=89 \[ -\frac{a (4 A b-3 a B) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 b^{5/2}}+\frac{x \sqrt{a+b x^2} (4 A b-3 a B)}{8 b^2}+\frac{B x^3 \sqrt{a+b x^2}}{4 b} \]
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Rubi [A] time = 0.127204, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182 \[ -\frac{a (4 A b-3 a B) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 b^{5/2}}+\frac{x \sqrt{a+b x^2} (4 A b-3 a B)}{8 b^2}+\frac{B x^3 \sqrt{a+b x^2}}{4 b} \]
Antiderivative was successfully verified.
[In] Int[(x^2*(A + B*x^2))/Sqrt[a + b*x^2],x]
[Out]
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Rubi in Sympy [A] time = 15.1568, size = 82, normalized size = 0.92 \[ \frac{B x^{3} \sqrt{a + b x^{2}}}{4 b} - \frac{a \left (4 A b - 3 B a\right ) \operatorname{atanh}{\left (\frac{\sqrt{b} x}{\sqrt{a + b x^{2}}} \right )}}{8 b^{\frac{5}{2}}} + \frac{x \sqrt{a + b x^{2}} \left (4 A b - 3 B a\right )}{8 b^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**2*(B*x**2+A)/(b*x**2+a)**(1/2),x)
[Out]
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Mathematica [A] time = 0.0728713, size = 77, normalized size = 0.87 \[ \frac{\sqrt{b} x \sqrt{a+b x^2} \left (-3 a B+4 A b+2 b B x^2\right )+a (3 a B-4 A b) \log \left (\sqrt{b} \sqrt{a+b x^2}+b x\right )}{8 b^{5/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(x^2*(A + B*x^2))/Sqrt[a + b*x^2],x]
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Maple [A] time = 0.01, size = 101, normalized size = 1.1 \[{\frac{Ax}{2\,b}\sqrt{b{x}^{2}+a}}-{\frac{Aa}{2}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){b}^{-{\frac{3}{2}}}}+{\frac{{x}^{3}B}{4\,b}\sqrt{b{x}^{2}+a}}-{\frac{3\,Bxa}{8\,{b}^{2}}\sqrt{b{x}^{2}+a}}+{\frac{3\,{a}^{2}B}{8}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){b}^{-{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^2*(B*x^2+A)/(b*x^2+a)^(1/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*x^2/sqrt(b*x^2 + a),x, algorithm="maxima")
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Fricas [A] time = 0.243589, size = 1, normalized size = 0.01 \[ \left [\frac{2 \,{\left (2 \, B b x^{3} -{\left (3 \, B a - 4 \, A b\right )} x\right )} \sqrt{b x^{2} + a} \sqrt{b} -{\left (3 \, B a^{2} - 4 \, A a b\right )} \log \left (2 \, \sqrt{b x^{2} + a} b x -{\left (2 \, b x^{2} + a\right )} \sqrt{b}\right )}{16 \, b^{\frac{5}{2}}}, \frac{{\left (2 \, B b x^{3} -{\left (3 \, B a - 4 \, A b\right )} x\right )} \sqrt{b x^{2} + a} \sqrt{-b} +{\left (3 \, B a^{2} - 4 \, A a b\right )} \arctan \left (\frac{\sqrt{-b} x}{\sqrt{b x^{2} + a}}\right )}{8 \, \sqrt{-b} b^{2}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*x^2/sqrt(b*x^2 + a),x, algorithm="fricas")
[Out]
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Sympy [A] time = 19.907, size = 150, normalized size = 1.69 \[ \frac{A \sqrt{a} x \sqrt{1 + \frac{b x^{2}}{a}}}{2 b} - \frac{A a \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{2 b^{\frac{3}{2}}} - \frac{3 B a^{\frac{3}{2}} x}{8 b^{2} \sqrt{1 + \frac{b x^{2}}{a}}} - \frac{B \sqrt{a} x^{3}}{8 b \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{3 B a^{2} \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{8 b^{\frac{5}{2}}} + \frac{B x^{5}}{4 \sqrt{a} \sqrt{1 + \frac{b x^{2}}{a}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**2*(B*x**2+A)/(b*x**2+a)**(1/2),x)
[Out]
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GIAC/XCAS [A] time = 0.246939, size = 101, normalized size = 1.13 \[ \frac{1}{8} \, \sqrt{b x^{2} + a}{\left (\frac{2 \, B x^{2}}{b} - \frac{3 \, B a b - 4 \, A b^{2}}{b^{3}}\right )} x - \frac{{\left (3 \, B a^{2} - 4 \, A a b\right )}{\rm ln}\left ({\left | -\sqrt{b} x + \sqrt{b x^{2} + a} \right |}\right )}{8 \, b^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*x^2/sqrt(b*x^2 + a),x, algorithm="giac")
[Out]